I' m new here
I' m casio fx-7400G owner, and was wondering about creating a program to do "a mod b" in a easy way, instead of using the subtraction one.
is it a common a question?
can you help me?
hope this is the right section, thank you
Mod Function ( A Mod B) How To
Started by
adrios
, Sep 01 2012 02:25 PM
1 reply to this topic
#1
adrios
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fx 7400g
Posted 01 September 2012 - 02:25 PM
Hi!
I' m new here
I' m casio fx-7400G owner, and was wondering about creating a program to do "a mod b" in a easy way, instead of using the subtraction one.
is it a common a question?
can you help me?
hope this is the right section, thank you
I' m new here
I' m casio fx-7400G owner, and was wondering about creating a program to do "a mod b" in a easy way, instead of using the subtraction one.
is it a common a question?
can you help me?
hope this is the right section, thank you
#2
MicroPro
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Casio Overlord
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- Location:Iran
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Calculators:
Casio ClassPad 300
Posted 25 September 2012 - 02:03 PM
Welcome to UCF, adrios! Introduce yourself here.
What do you want to do? a mod b can be calculated by b * (a/b - int(a/b)). ("int" is the integer part function)
So there is no need to subtractions.
I may not have understood you correctly. Please explain more?
What do you want to do? a mod b can be calculated by b * (a/b - int(a/b)). ("int" is the integer part function)
So there is no need to subtractions.
I may not have understood you correctly. Please explain more?
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