Hello everyone,

I wanna find solution of equation:

$(1-i)\left| z \right|^2 + (2+2i)z^2+2z(z+i)=0$ by Newton Raphson method.

It’s difficult to compute derivative of $\left|z \right|$. So I assumed:${\left( {{{\left| z \right|}^2}} \right)^\prime } = 0$

(We can use ANS, or $X=X-\dfrac{f(X)}{f'(X)}$ to compute Newton Raphson)

And I was lucky, I obtain the solution $z=\dfrac{-1}{3}-\dfrac{5}{9i}$.

Where is the wrong answer?

**Edited by bichthuancasio, 29 May 2017 - 10:15 AM.**