Best Answer TBit , 28 March 2020 - 03:04 AM
I think it depends on which compiler you are using (I assume gcc).
So maybe try different optimization options first. Also, you could make your function pointer constant, like this:
void (*const i)(int, int)
For Casio's SHC, you could try different optimization arguments (-speed, -nospeed,-size) or maybe a
#pragma sectionGo to the full post
Casio Fan
Posted 28 March 2020 - 01:45 AM
I noticed that this code:
void (* i)(int, int) = (void*)0x0;
int main(int isAppli, int OptionNum) {
i(1, 1);
return 1;
}
generates this:
300318: d1 04 mov.l 0x30032c,r1 ! 8100004 30031a: e5 01 mov #1,r5 30031c: 4f 22 sts.l pr,@-r15 30031e: 61 12 mov.l @r1,r1 300320: 41 0b jsr @r1 300322: e4 01 mov #1,r4
It seems like the compiler is putting the pointer of the function i into the .data section. Is there any way to change this behavior so that it puts the raw 0x0 pointer into .rodata so that it doesn't need the mov.l @r1,r1?
Edited by hejsotnoss, 28 March 2020 - 02:01 AM.
Newbie
Posted 28 March 2020 - 03:04 AM Best Answer
I think it depends on which compiler you are using (I assume gcc).
So maybe try different optimization options first. Also, you could make your function pointer constant, like this:
void (*const i)(int, int)
For Casio's SHC, you could try different optimization arguments (-speed, -nospeed,-size) or maybe a
#pragma section
Casio Fan
Posted 28 March 2020 - 03:40 AM
Thank you, a combination of using -O3 and and making the function pointer constant seemed to fix my issue. 
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