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Fx-850P Basic Code


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#1 CasioRich

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Posted 08 October 2012 - 11:00 AM

Hi all,

Please help:

I have some BASIC code from a program on a Casio FX-850P calculator that I would like to convert into C++ and make into a Windows application using Visual Studio - any suggestions?

#2 flyingfisch

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Posted 08 October 2012 - 02:46 PM

Hello CasioRich and welcome to UCF! You should introduce yourself.

Well, I think you would have to manually port it. It probably would not be too difficult. Would you like to share your program so we can see?

#3 CasioRich

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Posted 09 October 2012 - 12:59 PM

Hi flyingfisch,

I will introduce myself properly at the link you posted when I get a bit time but I'm under pressure from work to get stuff done atm.

I could port it, the code isn't too complex - it basically calculates a brace betweeen two struts in the engineering/fabrication we do.

Here is the code I took out of the calculator:

1 'HFG BRACING CALCS
2 CLS:CLEAR
10 DIM C(2),I(2),O(2),W(2),LA(2),LB(2),LC(2),PLUS(2),SJ(2),JH(2),REV$(2),01(2),BRI(2),TRAV(2) *****NOTE ZEROS OR ONES???
20 ANGLE 0:SET N
100 PRINT "Brace or Stub";CHR$(13);
110 A$=INKEY$
120 IF A$="B" OR A$="b" THEN EDS=2:T$"BRACE":GOTO 1000
130 IF A$-"S" OR A$="s" THEN EDS=1:I(2)=90:T$="STUB":GOTO 1000
140 GOTO 110
1000 '**********INPUTS**************
1010 PRINT T$;:INPUT " DIA ";BD:IF BD <=0 THEN BEEP:GOTO 1010
1020 INPUT "WALL THICKNESS";WT:BRI=(BD/2)-WT
1030 IF WT<0 OR WT>BD/2 THEN BEEP:GOTO 1020
1050 FOR N=1 TO EDS
1060 PRINT "END";N;CAN DIA";CHR$(13);"EXE=STR CUT";:INPUT C(N):IF N=1 AND C(1)<0 THEN BEEP:GOTO 1060
1064 IF N=2 AND C(2) <0 THEN C(2)=C(1):I(2)=I(1) <img src='/dot/public/style_emoticons/<#EMO_DIR#>/ohmy.png' class='bbc_emoticon' alt=':o' />(2)=O(1):W(2)=W(1):BRI(2)=BRI(1):SYM=1:LA(2)=LA(1):LB(2)=LB(1):LC(2)1=LC(1):O1(2)=O1(1):GOTO 1110
1079 CLS
1080 PRINT "END ";N;"WELD PREP Y or N";CHR$(13);
1081 A$=INKEY$
1082 IF A$="Y" OR A$="y" THEN W(N)=1:BRI(N)=BRI:GOTO 1090
1083 IF A$="N" OR A$="n" THEN W(N)=0:BRI(N)=BRI+WT:GOTO 1090
1084 GOTO 1081
1090 CLS:PRINT "END ";N;" INCLUDED ANGLE ";:INPUT I(N):IF I(N)<=0 OR I(N) >90 THEN BEEP:GOTO 1090
1092 IF I(N)<=37.5 AND W(N)=1 THEN PRITN "REV PREP";CHR$(13);
1093 IF C(N)=0 THEN 1097
1094 PRINT "END ";N;" OFFSET";:INPUT O(N)
1095 IF O(N)<0 THEN BEEP:GOTO 1094
1096 IF BRI(N)+O(N)>C(N)/2 THEN BEEP:GOTO 1094
1097 O1(N)=(C(N)/2)-SQR(((C(N)/2)^2)-(O(N)^2))
1100 C(N)=C(N)/2:LA(N)=C(N)/SIN(I(N)):IF I(N)<90 THEN LB(N)=BRI/TAN(I(N))
1102 IF I(N) <> 90 THEN LC(N)=WT/TAN(I(N))
1110 NEXT N
1111 FOR N=1 TO EDS
1115 GOSUB 3400
1116 NEXT N
1119 CLS
1120 INPUT "INTERS";CTRS
1130 IF CTRS<LA(1)+LA(2)+LB(1)+LB(2)+LC(1)+LC(2)+PLUS(1)+PLUS(2) THEN BEEP:PRINT "NOT ENOUGH";CHR$(13):;GOTO 1120
3000 '************CALCULATIONS*******
3001 SJ(1)=LA(1)-LB(1)-O1(1)/SIN(I(1)):SJ(2)=LA(2)-LB(2)-O1(2)/SIN(I(2))
3002 JH(1)=LB(1)*2+O1/SIN(I(1)):IF I(1)<=37.5 AND W(1)=1 THEN JH(1)=JH(1)+LC(1)
3003 JH(2)=LB(2)*2+O1(2)/SIN(I(2)):IF I(2)<=37.5 AND W(2)=1 THEN JH(2)=JH(2)+LC(2)
3005 SJ(1)=INT(SJ(1)+.5):SJ(2)=INT (SJ(2)+.5):JH(1)=INT(JH(1)+.5):JH(2)=INT(JH(2)+.5)
3010 JESCO=CTRS-SJ(1)-SJ(2)
3020 HGG=JESCO-JH(1)-JH(2)
3022 IF I(1)<=37.5 AND W(1)=1 THEN REV$(1)="REV PREP"
3024 IF I(2)<=37.5 AND EDS=2 AND W(2)=1 THEN REV$(2)="REV PREP"
3030 LGTH=CTRS-LA(1)-LA(2)+LB(1)+LB(2)+INT(.5+PLUS(1))+INT(PLUS(2)+.5)
3040 WGHT=(((HGG+LGTH)/2*PI*(BD-WT))*7.85*WT*.000001
3050 SA=((HGG+LGTH)/2)*PI*BD*.000001
3075 LGTH=INT(LGTH+.5):WGHT=INT(WGHT+.5):SA=ROUND(SA,-3):TRAV(1)=INT(TRAV(1)+.5):TRAV(2)=INT(TRAV(2)+.5)
3300 GOTO 9000
3390 '*******CALCS INC IN LGTH
3400 ROT=1:COUNT=1
3405 IF SYM=1 AND N2= THEN PLUS(2)=PLUS(1):TRAV(2)=TRAV(2)=TRAV(1):GOTO 3670
3410 IF I(N)=90 THEN TRAV(N)=C(N)-SQR(C(N)^2-(O(N)+BR(N)^2):PLUS(N)=TRAV(N):GOTO 3670
3420 IF C(N)=0 AND W(N)=0 THEN PLUS(N)=LC(N):GOTO 3670
3430 IF C(N)=0 AND W(N)=1 THEN GOTO 3670
3500 A1=(BRI(N)*SIN(ROT))+0(N)
3505 CLS:PRINT "CALCULATING END";N;ROT;CHR$(8);CHR$(223);
3510 B1=SQR((C(N)^2)-(A1^2))
3520 C1=C(N)-B1
3530 D1=(BRI(N)-BRI(N)*COS(ROT))/TAN(I(N))
3540 E1=C1/SIN(I(N))
3550 F1=E1-D1
3560 IF F1>PLUS(N) THEN ROT=ROT+5:PLUS(N)=F1:COUNT=2:GOTO 3500
3570 IF COUNT=1 THEN RETURN
3580 ROT=ROT-4
3600 A1=(BRI(N)*SIN(ROT))+0(N)
3605 CLS:PRINT "CALCULATING END";N;ROT;CHR$(8);CHR$(223);
3610 B1=SQR(C(N)^A1^2)
3620 C1=C(N)-B1
3630 D1=(BRI(N)-(BRI(N)*COS(ROT)))/TAN(I(N))
3640 E1=C1/SIN(I(N))
3650 F1-E1-D1
3660 IF F1>PLUS(N) THEN ROT=ROT+1:PLUS(N)=F1:GOTO 3600
3670 RETURN
9000 '********************OUTPUTS************
9010 CLS
9020 PRINT "BRACE LENGTH =";LGTH;CHR$(13);"BRACE WEIGHT =";WGHT;"kg"
9030 PRINT "SURF. AREA-";SA:CLS
9040 PRINT "O/ST POINTS (JESCO)=";JESCO;CHR$(13);
9050 PRINT "INI LENGTH (HGG)=";HGG
9060 PRINT "SOP TO JES 1=";SJ(1):CHR$(13);
9070 IF I(1)<90 THEN PRINT "JES TO HGG 1=";JH(1);REV$(1)
9075 IF I(1)=90 THEN RPINT "TRAVEL=";TRAV(1)
9080 IF EDS=2 THEN PRINT "SOP TO JES 2=";SJ(2);CHR$(13);
9090 IF EDS=2 AND I(2)<90 THEN PRINT "JES TO HGG 2=";JH(2);REV$(2)
9100 IF I(2)=90 AND EDS=2 THEN PRINT "TRAVEL=";TRAV(2)
9500 END


#4 flyingfisch

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Posted 09 October 2012 - 03:31 PM

Do you want the computer version to have a GUI or is it just a command line program?

If you want a GUI, it may be a good idea to do it from scratch and use this program sort of as an outline for the math part...

#5 CasioRich

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Posted 09 October 2012 - 03:41 PM

Really it would be best with a GUI.

I could just create it using that as a template but I'm not really a good coder yet.

#6 flyingfisch

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Posted 10 October 2012 - 03:11 AM

Ah, OK.

I think the easiest way would be just to port the code that does the calculations, and use the template to take care of user input, etc. ;)

#7 MicroPro

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Posted 02 November 2012 - 12:23 PM

Now I review your code, it doesn't have special code that could make it unportable. PRINT would be cout, INPUT is cin, INKEY could be cin.get, and fortunately goto is still there in C++. But anyway if you can get the algorithm and implement it yourself you'll have a cleaner program.

#8 flyingfisch

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Posted 02 November 2012 - 03:09 PM

You could go through your code and try to figure out how to do it without goto. Its almost always possible to do it with loops. ;)

#9 MicroPro

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Posted 07 November 2012 - 01:21 PM

It's possible; going through the code for converting it is another story. The following is an example from my textbook which really challenged me, see what about you? :)
    int row = 0,
	    col;
A:    col = 0;
    if (col < n) goto B;
    goto A;
B:    if (row < n) goto C;
    goto E;
C:    if (mat[row][col] == item) goto D;
    col++;
    if (col < n) goto B;
    row++;
    goto A;
D:    cout << "Item found\n";
    goto F;
E:    cout << "Item not found\n";
F:





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