third square root of i
#1
Posted 12 February 2004 - 05:52 PM
by typing
(3) -> (SHIFT) -> (^) -> (OPTN) -> (CPLX) -> (i)
i only get a MATH ERROR. what shall i do?
please help, greg from lake constance.
#2
Posted 12 February 2004 - 07:00 PM
0.8660254038+0.5i
#3
Posted 12 February 2004 - 07:03 PM
third roots of i :
-i
-sqrt(3)/2 + i/2
sqrt(3)/2 + i/2
#4
Posted 12 February 2004 - 07:03 PM
----------EDIT-----------
overlord beat me to it...
#5
Posted 12 February 2004 - 08:26 PM
is afx = algebra fx 2.0 ????
#6
Posted 12 February 2004 - 08:50 PM
so algebra fx 2.0 is one of the AFX model calcs
#7
Posted 12 February 2004 - 09:11 PM
#8
Posted 13 February 2004 - 07:52 AM
well, i am just learning complex numbers at school now with my CFX, and we can do simple complex number calculations with the CFX.it's because the CFX is not adapted for complex calculations.
eg. (4+5i)(5+3i) or division or just plain + and -.
We will use progs for the other more complicated stuff like roots, powers.
i'll may be able to answer you question soon, if i learn about third root of i
#9
Posted 13 February 2004 - 05:11 PM
#10
Posted 13 February 2004 - 11:21 PM
Went into CAS mode
Set answers to complex mode
typed solve(x^3=i,x)
Well, the calc did not bring the correct answer but the output was very interesting (too long to type) so I suggest Horny to try what I did.
Greets
Coco
#11
Posted 14 February 2004 - 09:58 AM
z=a+bi, you want the xth roots of z.
you convert z=a+bi in z = r*e^(i@) = r*cis(@)=r*(cos(@)+isin(@) (it's the same)
- Pol(a,b) will give as result List Ans={r,@} **** (menu angle)
- Abs(a+bi) will give as result Ans=r **** (menu cplx)
- Arg(a+bi) will give as result Ans=@ **** (menu cplx)
- AFX : you have a command to convert automatically z=a+bi in z=r*e^(i@)=r*cis(@)
(check rad/deg mode, i work in rad)
z = r*cis(@) = r*cis(@+2kpi) **** k integer
the x xth roots of z are :
x1 = x-root( r )*cis( (@+2kpi)/x ) [for k=0] = x-root( r )*cis( @/x )
x2 = x-root( r )*cis( (@+2kpi)/x ) [for k=1] = x-root( r )*cis( @/x + 2pi/x)
x3 = ...
x4 = ...
then you can convert it x=c+di
- Rect(r,@) will give as result List Ans={c,d}
- ReP(r*cis(@)) will give as result Ans=c
- ImP(r*cis(@)) will give as result Ans=d
- AFX : you have a command to convert automatically x=r'*e^(i@')=r'*cis(@') in z=c+di
nota : i had a problem while typing this post, when i type ( r ) without the spaces, it automatically convert it in ®
#12
Posted 14 February 2004 - 11:29 AM
p.s. to coco: where can I set answer to complex mode?
#13
Posted 14 February 2004 - 11:28 PM
1. Choose option D (ALGBR) -- enters in ALGEBRA mode
2. Press Shift' /> MENU' /> -- enters the SETUP menu (press shift key first then menu key)
There are three options there: Angle (default is Rad), Answer type (default is Real) and Display (default is Norm1)
3. Highlight 'Answer type' then press F2 (this will change answer type to Complex)
4. Press
That's it.
Good luck
#14
Posted 15 February 2004 - 06:03 PM
#15
Posted 15 February 2004 - 11:59 PM
Coco
#16
Posted 16 February 2004 - 06:07 AM
thanks very much
@coco
i'm not very good in programming with the calc yet. could you send me the program? admin AT greg-bala.de thanks.
#17
Posted 16 February 2004 - 07:43 AM
#18
Posted 17 February 2004 - 09:12 AM
Coco.
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