# Simultaneous Equations

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### #1 fiberoptik

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Posted 29 October 2004 - 02:35 PM

Hello people, at last i have my CP and i'm enjoying it a lot, but a have a problem. The manual is very easy to understand but it has so few examples ! It doesn't tell us much!
I need to solve a equation system with 3 equations and three unknowns
Example:
2x+3y+4z=8
4x-3z+2y=6
6x+4y+8z=10

and i need to know x,y and z

Sorry to ask such a simple thing but i am short on time and my exams begin next week.

Thanks

### #2 CrimsonCasio

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Posted 29 October 2004 - 04:32 PM

use the 2d keyboard and find a button that looks like this: {|
thats the similtanios equasion solver.

{2x+3y+4z=8|
{4x-3z+2y=6|
{6x+4y+8z=10| x,y,z

### #3 fiberoptik

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Posted 29 October 2004 - 04:54 PM

Thank you very much for your help

### #4 Guest_Guest_*

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Posted 30 October 2004 - 12:28 AM

I've tried what you told me, but that function only let me put two equations, and i need three ! I'm i doing something wrong ?

Thanks

### #5 CrimsonCasio

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Posted 30 October 2004 - 01:30 AM

hit the button again to add more equations

### #6 Guest_Guest_*

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Posted 04 November 2004 - 04:08 AM

Excuse me... but where I should enter this equations ? how I should solve them ???

Thanks

### #7 CrimsonCasio

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Posted 04 November 2004 - 04:17 AM

i dont know how to describe it better...

{2x+3y+4z=8|
{4x-3z+2y=6|
{6x+4y+8z=10| x,y,z (hit enter)

### #8 fiberoptik

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Posted 04 November 2004 - 11:08 AM

Thank you Crimson (can i call you this way ? )
Now i know how to solve systems with 2,3,4... equations.

Thanks

### #9 CrimsonCasio

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Posted 04 November 2004 - 11:47 AM

sure

### #10 Guest_Guest_*

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Posted 05 November 2004 - 03:50 AM

Excuse me... maybe there is an error but I could not solve multiple equations this way.

For example, defining

x=1
y=2
z=3

this way

2x+2y=6
1x+2z=7
3y+2z=10

inputing these equations in main application like

{2x+2y=6| x+2z=7| 3y+2z=10|x,y,z} and hiting enter, the CP return
{2x+2y=6,y,z}

I'im searching for something that solves these equations and result the same as rref() would result for this matrix...

[ 2 2 0 6 ]
[ 1 0 2 7 ] // coeficient matrix | b
[ 0 3 2 10]

this is possible ?

### #11 fiberoptik

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Posted 05 November 2004 - 10:54 AM

I have tried your example and the answer was {x=((3)/(2)),y=((3)/(2)),z=((11)/(4))}. Explain me better :

"For example, defining

x=1
y=2
z=3 "

I didn't understand this part

### #12 Guest_Guest_*

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Posted 05 November 2004 - 07:42 PM

I defined these values for variables x, y and z

x=1
y=2
z=3

these values, make the left side of equation = right side...

this way

2x+2y=6 (2 * (1) + 2 * (2) + 0 * (3)= 2 + 4 = 6)
1x+2z=7 (1 * (1) + 0 * (2) + 2 * (3) = 1 + 6 = 7)
3y+2z=12 (0 * (1) + 3 * (2) +2 * (3) = 6 + 6 = 12)

I would like to know if there is a way to enter these equations and the CP return the values of X, Y, Z.

If I take this equations, and build a matrix, I can calculate with rref(). The returned matrix will have the value of X, Y and Z.

I would like to know if there is a function to solve this linear system only with equations.

Thanks

### #13 fiberoptik

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Posted 06 November 2004 - 11:17 AM

Hi
quoting from a previous post from CrimsonCasio

"
{2x+3y+4z=8|
{4x-3z+2y=6|
{6x+4y+8z=10| x,y,z (hit enter)"

go to the 2D separator in the keyboard and find this symbol { |, then tap the symbol the n- of equations you need, (if you tap one time you get 2 equations, tap 2 times get 3 equations and so on), next write the equations and finally write the unknowns you need. look at the example above.

### #14 Guest_Guest_*

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Posted 07 November 2004 - 02:11 AM

I realy do not know where or how you solve these equations. I've tried a lot of time, in diferent applications. First, I tried in main, copying *. After, with the same data, inputing in NumSolve, the "Incorrect number of parenthesis" error was shown.

* "
{2x+3y+4z=8|
{4x-3z+2y=6|
{6x+4y+8z=10| x,y,z (hit enter)"

Somebody realy did this code solve multiple equations ??? where ??? Main, NumSolve ???

Well, I found that Solve() support multiple linear equations (and works well). Solving this system:

solve({2x+3y+4z=8, 4x-3z+2y=6, 6x+4y+8z=10}, {x, y, z})

the solution is {x=-1/13, y=38/13, z=-2/13}

Thanks

### #15 Guest_Guest_*

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Posted 07 November 2004 - 02:14 AM

Excuse me
I found the {| button

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