If I have a function f(x) e.g. f(x)=x^2 and let the CP draw the graph I get the whole graph. Now i need only the part where (e.g.) x>0 (I think this is called "domain" in english). How do I add that? Is it possible?
~timppa
Domains Of Functions
Started by
timppa1988
, Dec 06 2004 04:15 PM
7 replies to this topic
#2
abelmartin
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Posted 06 December 2004 - 04:30 PM
y=x^2|x>0
keyboard mth OPC | x > 0 enter
keyboard mth OPC | x > 0 enter
#3
timppa1988
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Posted 06 December 2004 - 04:34 PM
Thanks, that's what I was searching for 
#4
timppa1988
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Posted 06 December 2004 - 04:54 PM
Ok it works with the graph but if I type solve((x^2=9)|x>0,x) it says {x=-3,x=3}. With solve((x^2=9)|x>3,x) it says "No Solution" which is correct. Why is that so?
#5
UserC300
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Posted 06 December 2004 - 06:28 PM
Both are!
{x=-3,x=3} is the solution, by excluding it (x>3) there is "No Solution".
{x=-3,x=3} is the solution, by excluding it (x>3) there is "No Solution".
#6
timppa1988
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Posted 06 December 2004 - 09:10 PM
Yeah, of course both are solutions but i typed solve((x^2=9)|x>0,x) so that the only answer should be {x=3} shouldn't it?
#7
abelmartin
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Posted 07 December 2004 - 09:08 AM
Pardon, but I do not speak English
Graphic
y=x^2|x>0
y=9
G solve intersect
x=3
Graphic
y=x^2|x>0
y=9
G solve intersect
x=3
#8
Guest_Salomon_*
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Posted 13 February 2005 - 11:01 PM
Yeah, of course both are solutions but i typed solve((x^2=9)|x>0,x) so that the only answer should be {x=3} shouldn't it?
You should write solve(x^2=9)|x>0, no parenthesis outside the expresion!, because the operator "|" is a general operator, it is not a solve operator, therefore solve ignore it.
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