In French :
Bonjour, je viens d'acquerir la Casio Class pad 300+ et j'aimerai savoir si il existe une fonction qui permet de r?soudre cette equation
(-x^3+5x)/(x?+3) = ax + (bx)/(x?+3)
L'objectif est de trouver a et b
Je l'ai fais a la main et j'ai trouv? a = -1 et b = 8. ce sont les resultats et j'en suis sur mais je voudrais tout de meme savoir si la calculatrice a une fonction permettant de resoudre cette ?quation
In english
Hello, i get a classpad 300 yesterday, and i want to know if there is a function who can solv this
(-x^3+5x)/(x?+3) = ax + (bx)/(x?+3)
The target is to find a and b
The result is a = -1 and b - 8 but i want to know who solv it with the classpad
Thanks
Unknow Function
Started by
Berserendo
, Mar 13 2006 10:56 AM
2 replies to this topic
#1
Posted 13 March 2006 - 10:56 AM
#2
Posted 14 March 2006 - 08:53 AM
You should write this in the Main application:
solve((-x^3+5x)/(x?+3) = ax + (bx)/(x?+3), a, b )
Also if x is defined you can use the NumSolve application...
(I'm not sure that CP can solve this...)
solve((-x^3+5x)/(x?+3) = ax + (bx)/(x?+3), a, b )
Also if x is defined you can use the NumSolve application...
(I'm not sure that CP can solve this...)
#3
Posted 14 March 2006 - 12:28 PM
You should write this in the Main application:
solve((-x^3+5x)/(x?+3) = ax + (bx)/(x?+3), a, b )
Also if x is defined you can use the NumSolve application...
(I'm not sure that CP can solve this...)
I tried... and nothing, with NumSolve also... maybe someone else had luck?
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