r=t^2,
=ARCTAN(t^2/(t+t^2)It is just like:
x=f(t), y=g(t).
I need your help
Trouble With Graph
Started by
Behnoud
, Jun 19 2006 06:59 PM
5 replies to this topic
#1
Behnoud
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Posted 19 June 2006 - 06:59 PM
How I can plot a polar function like:
r=t^2, =ARCTAN(t^2/(t+t^2)
It is just like:
x=f(t), y=g(t).
I need your help
r=t^2,
=ARCTAN(t^2/(t+t^2)It is just like:
x=f(t), y=g(t).
I need your help
#2
vanhoa
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Posted 20 June 2006 - 04:03 AM
Hi.
The CP do not have that function as i kniow so far. I think that you should write a program to do that, using the translate fomula: polar
rectangular : (r, ) (r*cos( ),r*sin( )).
I hope it will help you
.
The CP do not have that function as i kniow so far. I think that you should write a program to do that, using the translate fomula: polar
rectangular : (r, ) (r*cos( ),r*sin( )).I hope it will help you
.
#3
Behnoud
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Posted 20 June 2006 - 05:45 PM
I need it urgently!
I have an exam on next few days
I haven't written any program for CP
I have an exam on next few days
I haven't written any program for CP
#4
SoftCalc
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Posted 21 June 2006 - 04:31 AM
Use the parametric graph type [xt]I need it urgently!
I have an exam on next few days
I haven't written any program for CP
#5
Behnoud
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Posted 06 July 2006 - 06:07 AM
Thanks Softcalc and Vanhoa.
It worked properly.
It was a good Idea.
How silly I was.
It worked properly.
It was a good Idea.
How silly I was.
#6
Behnoud
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Posted 30 September 2006 - 05:30 PM
How I can Plot something like:
x^2-y^2 >1 ?
x^2-y^2 >1 ?
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