5 replies to this topic

[Cegafi]

Hola. ¿Cómo puedo simplificar (x^5)^(1/2) para que la calculadora me de como resultado (x^2)(x^(1/2))? Gracias por su ayuda.

How can I simplify (x^5)^(1/2) . I want to get (x^2)(x^(1/2)). Or how can I simplify (81*x^7*y^11)^(1/3). Thanks for your help.

Edited by Cegafi, 27 October 2010 - 05:10 AM.

[Cegafi]

Thanks, but I want to know how to get the correct answer in the classpad. I know the laws of exponents. But I can't get it in the classpad.

[MicroPro]

Hi.
You didn't mention how much you know about classpad so i try to be as clear as possible.
When you enter a variable such as x the classpad doesn't know whether it is positive or negative. This is important when you want to work with radical signs and roots in a calculator. So replace x with abs(x) (select x, go to 2d tab of keyboard and tap |▪| icon). Any of the functions collect, combine, factor, simplify, etc can simplify that expression for you.

For example go to Main and type this: simplify((abs(x)^5)^(1/2)) EXE' />
(Your 2nd Expression:)
collect(81*(abs(x))^7*(abs(y))^11)^(1/3) EXE' />
simplify((81*(abs(x))^7*(abs(y))^11)^(1/3) EXE' />

Edited by MicroPro, 29 October 2010 - 03:03 PM.

[william turner]

the simplify radicals are belong to quadratic equation that simplify the major and minor root cubic root and eliminate the radicals the given example help to solve the simplify the radicals
Simplest radical form means simplifying a radical so that there are no more square roots, cube roots, 4th roots and such left to find. It also means removing any radicals in the denominator of a fraction.

For example, look at √8

Since 8 = 4 * 2

√8 = √(4 * 2)

Since 4 = 2 * 2 it is a perfect square. So take the square root of that number, and thereby take it out of the radical. In other words,
√2 * √2 = 2

So then:

√8 = √(4 * 2) = √2 * √2 * √2

= 2√2

When you solve a problem using the quadratic formula, you are being asked to use this type of method of simplifying.for kind of problem related to algebra and radical expression visit the link.