3 replies to this topic

[Naga]

Hello everyone,

I am having following calculation line in my basic program.

B= Time in seconds eg: 3943

Int (B / 3600) -> H -(hour)
Int ((B-(H X 3600)) / 60) ->M (Minutes)
Int (B-((H X 3600)+(M X 60))) -> S (Seconds)
Now the time is 1 hour 5 minutes and 43 seconds

Suppose it is greater than 43.5000 seconds then I should print 44 Seconds

If it is less than 43.5000 seconds I should print 43 Seconds.

Anyone please help.

In my program am getting 40.735502 seconds I need to print it as 41 seconds.

[flyingfisch]

well, you could set rounding to Fix 0, but the best way would be to use LuaFX or C and access the RTC to make a timer.

[Casimo]

You can round like this Int(S + .5).

Edited by Casimo, 06 February 2013 - 06:13 PM.

[flyingfisch]

thats probably better as there will be no decimal point if you do it that way.