
Best Answer azogtoth , 15 February 2017 - 11:46 AM
found it! Try:
expand(1/(x^2-1),x)
Btw, I like typing
expand(1/(xx-1),x)
xx is easier to type than x^2, but works the same

Best Answer azogtoth , 15 February 2017 - 11:46 AM
found it! Try:
expand(1/(x^2-1),x)
Btw, I like typing
expand(1/(xx-1),x)
xx is easier to type than x^2, but works the same
Posted 15 February 2017 - 09:43 AM
Hello,
I need to do partial fraction decomposition:
simple example:
1/(x^2-1) -> (1/2)/(x-1) + (-1/2)/(x+1)
I was hoping expand(1/(x^2-1)) would do the trick, but unfortunately...
Does anyone know if there is a function on that can do this?
Otherwise, I'd have to write my own function to do this. But I struggle with how to pass a function to my function
Cheers,
Stefan
Posted 15 February 2017 - 11:46 AM Best Answer
found it! Try:
expand(1/(x^2-1),x)
Btw, I like typing
expand(1/(xx-1),x)
xx is easier to type than x^2, but works the same
0 members, 1 guests, 0 anonymous users