2 replies to this topic

[hejsotnoss]

I noticed that this code:

void (* i)(int, int) = (void*)0x0;

int main(int isAppli, int OptionNum) {
        i(1, 1);
        return 1;
}

generates this:

  300318:       d1 04           mov.l   0x30032c,r1     ! 8100004
  30031a:       e5 01           mov     #1,r5
  30031c:       4f 22           sts.l   pr,@-r15
  30031e:       61 12           mov.l   @r1,r1
  300320:       41 0b           jsr     @r1
  300322:       e4 01           mov     #1,r4

It seems like the compiler is putting the pointer of the function i into the .data section. Is there any way to change this behavior so that it puts the raw 0x0 pointer into .rodata so that it doesn't need the mov.l @r1,r1?

Edited by hejsotnoss, 28 March 2020 - 02:01 AM.

[TBit]

I think it depends on which compiler you are using (I assume gcc).

So maybe try different optimization options first. Also, you could make your function pointer constant, like this:

void (*const i)(int, int)

For Casio's SHC, you could try different optimization arguments (-speed, -nospeed,-size) or maybe a 

#pragma section

[hejsotnoss]

Thank you, a combination of using -O3 and and making the function pointer constant seemed to fix my issue.