# Mathematical doubts

### #1

Posted 26 November 2003 - 09:26 PM

### #2

Posted 27 November 2003 - 07:57 AM

Salut

### #3

Posted 27 November 2003 - 10:35 PM

Graficar the function y=sen x

But, I want to only do it for discreet values of time (single for whole values of x), of such form that the continuous nonquedaria graph. I only want to see in the results points that represent an amplitude for each value of whole x.

I hope have understood to me.

### #4

Posted 28 November 2003 - 03:20 PM

First, the ideal:

y=sin(x)|x=int(x)

it is to say that grafique the function sin(x) when x is equal to the whole part of x (that will be fulfilled indeed when x is whole). If this works it will be demonstrated that the functional integration of classpad is superior to any thing that Casio has done previously.

Second, the not so ideal one

y=sin(x)|x=1

y=sin(x)|x=2

?

and so on until arriving at the value that interests to you

with this solution you can make in addition a program that in loop contains the inferior limit and the superior one to the values of x that you want to graficar.

I hope serves to you as aid

greetings

Coco

### #5

Posted 28 November 2003 - 09:58 PM

He would be to fill up for example list 1 with the values of the variable of the time (x), and list 2 doing loop with the values of list 1 and applying the corresponding equation to them, later to go to the statistic way and to graficar ready 1 against list 1 (something similar I did once in classpad).

Changing of subject, Jaime is a page of a called Colombian Rocks in who he makes a comparison of the characteristics between several models of graficadoras computers, looking for in google there are it easily or if not soon I pass the Link to you.

So long, thanks coco.

### #6

Posted 28 November 2003 - 11:11 PM

so long

### #7

Posted 29 November 2003 - 08:18 AM

### #8

Posted 29 November 2003 - 08:21 AM

### #9

Posted 30 November 2003 - 12:06 AM

### #10

Posted 01 December 2003 - 05:33 AM

### #11

Posted 16 December 2003 - 09:21 PM

This reply is intended so that the moved topics are at the top of the topics list in the ClassPad forum so that everyone reads them!

I'm sorry if you find any mistakes in the translation, but that's my best!

Good luck, and don't get bored from reading this post in all the other moved topics.

### #12

Posted 29 February 2004 - 05:35 AM

2) Is it possible convert with the classpad numbers between polar and rectangular mode? (as i think no...) Does somebody made a program/function for this?

3) I made a program in basic for an exam. I made this operation in the program:

?P(1+ro^2-2?ro?cos(lambda)?cos(lat)) ->s

(well its a root operation, some multiplications... I want to print the value of "s", i use the locate command, but this command dont print the numerical value, this print the expression. I know that in the main application when i have a result with parenthesis etc.., i obtain the numerical value pressing the button ".5 <- -> 1/2"k

The question is, how can i do this in the program?

Hope you can understand (and help) me.

### #13

Posted 29 February 2004 - 04:58 PM

(if not it calcs what it can and the resulting formula is stored in the variable)

### #14

Posted 29 February 2004 - 05:09 PM

### #15

Posted 18 March 2004 - 09:36 AM

Every Day it is very annoying for me, that there is no option(I could not find one) for changing the default output format of complex numbers, it`s always the trigonometric form(a+ib). So I use the compToPol-function a lot.

Now I tried to get at least an program-output of an complex number in polar-form, like: PrintNatural compToPol(a+ib)

It`s not working! The output is still a complex number in trigonometric form and best thing, it is a wrong result (compToPol(a+ib) "unequal" a+ib).

Is there a solution to this problem?

### #16

Posted 04 May 2004 - 02:42 AM

1/(1+e^(2*X))^.5

I cant solve it using the classpad.

### #17

Posted 04 May 2004 - 12:30 PM

1/(1+e^(2*X))^(1/2)

or use the square root directly.

I don't have a classpad to test this but i've tryed it in my HP and it was able to do the integral.

the problem here is that when you want to perform an exact integral you shouldn't use decimal values, if you need to replace them by a fraction.

Btw the result is:

(-ln(abs(sqrt(e^2*x)+1)+1)-ln(abs(sqrt(e^2*x)+1)-1))/2

### #18

Posted 05 May 2004 - 10:25 AM

Could someone help me to solve this problem on ClassPad ( geometry problem ).

Given a cubic ABCDA'B'C'D'. N is midpoint of B'C'.

a) Calculate the volume of ANBD'.

Determine the angle form by 2 lines BD' and AN.

c) What is the shortest distance between BD' and AN.

Thank you very much.

**i have deleted you other post, it was the same as this one. prolly a browser error**

- andy.davies

- andy.davies

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