Posted 01 January 2004 - 02:54 PM
What about you ?
Posted 09 January 2004 - 01:14 AM
You can draw abs(y)=x in Graph&Table. Just change graph type to x=.
For y^2=x^2, you can draw it in Conics.
For x^3+y^3=1, you have to change form: y=(1-x^3)^(1/3) and draw in Graph&Table.
For abs(y)=abs(x), it is changed to: y=abs(x) and y=-abs(x).
I always love to learn math through ClassPad 300.
Posted 09 January 2004 - 03:56 AM
mm.. how do you do that?
For y^2=x^2, you can draw it in Conics or change to: y=abs(x) and y=abs(x), then draw them in Graph&Table.
Also i think its the same the way you say and y=(x^2)/2.
Posted 09 January 2004 - 04:23 AM
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