Is there anybody who can help write the trinomial formula for fx-3650p?
For example. (a+bx+cx^2)^d
Input a,b,c and d
Output the constant term of all the power of x
Please give a hand!
I really need an expert!
Started by
Seraph
, Jul 05 2004 02:12 PM
9 replies to this topic
#1
Seraph
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fx-3650p fx-3900p fx-50
Posted 05 July 2004 - 02:12 PM
#2
Mohamed
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Posted 05 July 2004 - 08:31 PM
Could you explain please in a more clear way what the problem is?
What are the inputs and required outputs?
What are the inputs and required outputs?
#3
octobclrnts
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Posted 06 July 2004 - 03:56 PM
I think what you are saying is that you want to raise a quadratic equation to a power correct? In that case you would take the d root of the answers you obtain from the quadratic formula (-b[+/-](b^2-4ac)^(1/2))/2a where it is in the form y=ax^2+bx+c.
#4
Overlord
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Posted 07 July 2004 - 09:09 AM
i think he wants that :
input a, b, c, d | F = (a+bx+cx?)^d
output a_i | F = a_0 + a_1*x + a_2*x? + a_3*x^3 + ... + a_n*x^n
input a, b, c, d | F = (a+bx+cx?)^d
output a_i | F = a_0 + a_1*x + a_2*x? + a_3*x^3 + ... + a_n*x^n
#5
Seraph
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Posted 08 July 2004 - 05:35 AM
How clever you are! Overlord has got my idea. Can anyone write that program with the computing language of fx-3650p?
#6
Overlord
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Posted 08 July 2004 - 06:10 AM
i don't know fx3650p programming language 
#7
CrimsonCasio
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Posted 08 July 2004 - 06:37 AM
nor I...
still, on other calcs the input command would be:
"A"?->A
if that works for you then they may be the same.
still, on other calcs the input command would be:
"A"?->A
if that works for you then they may be the same.
#8
Seraph
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fx-3650p fx-3900p fx-50
Posted 12 July 2004 - 01:32 PM
I understand your symbols.
#9
Seraph
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Posted 15 July 2004 - 03:12 PM
Could anyone suggest a general formula for trinomial?
#10
Daruosh
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Posted 16 July 2004 - 07:14 AM
1) first convert (ax^2 + bx + c)^ 2 into (a'x + b')^2 + c'
2) use binomial coefficioent: ( A + B )^n = Sigma(nCr(n,i)A^(n-i)B^i) 0=<i=<n
(a'x+b')^2 is A
c' is B
I think you can continue
2) use binomial coefficioent: ( A + B )^n = Sigma(nCr(n,i)A^(n-i)B^i) 0=<i=<n
(a'x+b')^2 is A
c' is B
I think you can continue
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