
Circular Reference Error
#1
Posted 29 November 2005 - 01:44 PM
If i define a Pr function
Define Pr(x,y)=x*y/(x+y)
and i try to do
Pr( Pr(1,1),1) classpad returns me "Circular Reference" error. Why ?
Thanks.
Alvise
#2
Posted 30 November 2005 - 07:46 PM
x+1=>xwhen the variable x does not exist...
Can this help?
#3
Posted 01 December 2005 - 03:27 AM
but the calc returns a numer if i do : approx(sin(sin(2)))
#4
Posted 02 December 2005 - 11:08 AM

#5
Posted 19 December 2005 - 12:41 PM
Hello,
If i define a Pr function
Define Pr(x,y)=x*y/(x+y)
and I try to do
Pr( Pr(1,1),1) classpad returns me "Circular Reference" error. Why ?
Thanks.
Alvise
"Circular Reference" means that you have refered to a function into the own function. For example Pr(Pr()).
I think that if you create another function and use it to refer to the Pr function, it must solve the problem. I mean:
<The Pr Function> Define Pr(x,y)=x*y/(x+y) <The second function, "Pr2"> Define Pr2(x,y)=x*y/(x+y) <And this is how you call your functions inside each other> Pr( Pr2(1,1),1)
I hope this solves your problem. Tell me the result, if you liked (CPMicroPro<At>yahoo.com).

#6
Posted 19 December 2005 - 12:50 PM
I've seen this several times, but I will just post it once:Tell me the result, if you liked (CPMicroPro AT yahoo.com).
This is a forum here, so the results should be given together with the question and the answers, not only on individual emails. Perhaps there will be some other persons who will have the same questions and who will be glad to see here if the solutions you proposed were good or not

#7
Posted 22 December 2005 - 12:38 PM
I've seen this several times, but I will just post it once:
This is a forum here, so the results should be given together with the question and the answers, not only on individual emails. Perhaps there will be some other persons who will have the same questions and who will be glad to see here if the solutions you proposed were good or not



#8
Posted 22 December 2005 - 01:06 PM

It's in the "Option" on the top right corner of each topic.
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