Hi all!
I only use CPLua for programming.
But I do not know yet how to convert a string to a variable name.
Could someone help me?
Question About Cplua 0.8
Started by
Hobart
, Mar 14 2007 12:23 PM
3 replies to this topic
#1
Hobart
-
- Members
-
- 34 posts
Casio Fan
- Gender:Male
- Location:Germany (Saxony/Ore Mountains)
-
Calculators:
ClassPad 300
Posted 14 March 2007 - 12:23 PM
#2
The_AFX_Master
-
- [Legends]
-
- 519 posts
Casio Overlord
- Gender:Male
- Location:Black Mesa Research Facility (sector C)
- Interests:BASIC +FORTRAN 90+ C++.....and HALF LIFE
-
Calculators:
Casio Algebra FX 2.0 Plus, Casio fx 570 ms, Classpad 300, And a crowbar
Posted 14 March 2007 - 12:40 PM
wrong forum, moved
#3
Orwell
-
- Members
-
- 777 posts
Casio Overlord
- Gender:Male
- Location:Paris - France
-
Calculators:
Casio AFX 1.02 / Casio ClassPad 300
Posted 14 March 2007 - 07:46 PM
Well there is no special command to do that in Lua (as there is one in Basic)...
But one possibility is :
But one possibility is :
abc = 9 varName = "abc" print( getfenv()[varName] ) -- prints 9I hope it will help
#4
Hobart
-
- Members
-
- 34 posts
Casio Fan
- Gender:Male
- Location:Germany (Saxony/Ore Mountains)
-
Calculators:
ClassPad 300
Posted 16 March 2007 - 01:22 PM
Yes! It works!
Thank You much!
Thank You much!
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
