# How Can I Solve This?

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### #1 Tixa

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Posted 27 May 2007 - 12:48 PM

How can I solve a problema like this in my class pad?

[[7,5],[6,9]]*[,[y]]=[,3' />]

### #2 Colombia

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Posted 27 May 2007 - 01:51 PM

[[7,5],[6,9]]*[,[y]]
solve({ans[1,1]=4,ans[2,1]=3},{x,y})

### #3 Colombia

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Posted 27 May 2007 - 01:56 PM

Another way is:

[[7,5],[6,9]]^(-1)[,3' />]

this will give you

[[0.6363636364],[-0.09090909091]]

### #4 Tixa

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Posted 27 May 2007 - 02:06 PM

Thank you!!

### #5 pooyan

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Posted 05 June 2007 - 10:11 PM

How can i solve it by NumSolve ?

for example

X+Y=5
2X-Y=1

### #6 Behnoud

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Posted 06 June 2007 - 08:49 PM

You need to do this:
solve({x+y=5,2x-y=1},{x,y})

### #7 pooyan

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Posted 06 June 2007 - 10:32 PM

when i write solve({x+y=5,2x-y=1},{x,y}) in NumSolve and then press EXE, an error comes and says: Invalid Syntax

it means that it has problem in writing method?

if Yes, where?

Thanx

### #8 The_AFX_Master

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Posted 07 June 2007 - 12:59 AM

Did you read at least the basics of your users guide?.. you need to know at least what mode of the calculator is better to solve a problem. Catch some free time and read your users guide

### #9 Behnoud

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Posted 07 June 2007 - 05:30 AM

Write the syntax in Main window not Numsolve!

### #10 pooyan

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Posted 07 June 2007 - 08:25 AM

Did you read at least the basics of your users guide?.. you need to know at least what mode of the calculator is better to solve a problem. Catch some free time and read your users guide

I know that i should write it on Main, i wanted to know, is it possible to solve it by NumSolve or not

### #11 PAP

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Posted 07 June 2007 - 10:51 PM

I don't like that "is it possible to solve it by NumSolve or not", so my first intention was to tell you . Nevertheless, I will answer: No it's not possible. NumSolve is just a numerical root finding application, restricted to one-variable equations, and just one numerical method, which is not even apparent to the user. I personally never use it. You may be able to solve systems of equations (linear on nonlinear) using solve, but not always (only rather simple nonlinear systems can be solved). If you want something more powerful, use the functions included in my LNA library. You will find much more flexible equivalents to NumSolve or solve. For example, LNA's function Broyden is able to solve more complicated nonlinear systems, and usually much faster than solve. You will need to learn CPLua and LNA, but you will have much more powerful tools in your hands. In any case, NumSolve is very primitive, don't expect too much.

### #12 girdeux

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Posted 08 June 2007 - 04:19 PM

NumSolve only can solve one equation with one variable, but you can replace one variable in the other ecuation and put this one-variable-equation in NumSolve. But it's more easy solve it by hand.

### #13 PAP

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Posted 13 June 2007 - 10:29 PM

You can do that in simple systems, where it is possible to replace one variable; even than, it is a headache. Well, you should really try LNA's Broyden function; you will see that it's much more powerful than those tricks .

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