How to claculate a double integral on a specific surface in CP?

I need to calculate this:

(X^2*Y^2-a^4)/(X^2+Y^2-2*a) on a square surface

which each edge has a length of 2*a and

coordination origin is in center of square, in other hand

the integral limits for both X & Y are from -a to a.

Sorry for my po...or english and thanks in advance.

Btw, It is needed for my exam and is urgent!

# Double Integral

Started by
Behnoud
, Jun 15 2007 04:20 PM

4 replies to this topic

### #1

Posted 15 June 2007 - 04:20 PM

### #2

Posted 16 June 2007 - 12:04 AM

I think that you need to study something about Gauss Theorem or Divergence.

if i'm right, you need to calculated the divergence of the function (X^2*Y^2-a^4)/(X^2+Y^2-2*a)

and then calculated the volume of the cubic.

if i'm right, you need to calculated the divergence of the function (X^2*Y^2-a^4)/(X^2+Y^2-2*a)

and then calculated the volume of the cubic.

### #3

Posted 16 June 2007 - 05:18 PM

Explane more, please!

My math basis is week!

My math basis is week!

### #4

Posted 20 June 2007 - 08:53 PM

Two solutions: (1) try to calculate the double integral directly (in CP, you need to calculate the integral of an integral), (2) Convert the double integral to a curvilinear integral using Green's theorem. I suggest to try the first solution; if CP cannot compute the double integral directly. try the second solution.

### #5

Posted 21 June 2007 - 08:59 AM

It can calculate the integral of an integral,

but if you want it parametrically;

What about calculating on a specific surface for example an triangle?

Btw, I have forgotten Green theorem, Is it time consuming to use it claculate a double integral on CP?

but if you want it parametrically;

What about calculating on a specific surface for example an triangle?

Btw, I have forgotten Green theorem, Is it time consuming to use it claculate a double integral on CP?

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