How to claculate a double integral on a specific surface in CP?
I need to calculate this:
(X^2*Y^2-a^4)/(X^2+Y^2-2*a) on a square surface
which each edge has a length of 2*a and
coordination origin is in center of square, in other hand
the integral limits for both X & Y are from -a to a.
Sorry for my po...or english and thanks in advance.
Btw, It is needed for my exam and is urgent!
Double Integral
Started by
Behnoud
, Jun 15 2007 04:20 PM
4 replies to this topic
#1
Posted 15 June 2007 - 04:20 PM
#2
Posted 16 June 2007 - 12:04 AM
I think that you need to study something about Gauss Theorem or Divergence.
if i'm right, you need to calculated the divergence of the function (X^2*Y^2-a^4)/(X^2+Y^2-2*a)
and then calculated the volume of the cubic.
if i'm right, you need to calculated the divergence of the function (X^2*Y^2-a^4)/(X^2+Y^2-2*a)
and then calculated the volume of the cubic.
#3
Posted 16 June 2007 - 05:18 PM
Explane more, please!
My math basis is week!
My math basis is week!
#4
Posted 20 June 2007 - 08:53 PM
Two solutions: (1) try to calculate the double integral directly (in CP, you need to calculate the integral of an integral), (2) Convert the double integral to a curvilinear integral using Green's theorem. I suggest to try the first solution; if CP cannot compute the double integral directly. try the second solution.
#5
Posted 21 June 2007 - 08:59 AM
It can calculate the integral of an integral,
but if you want it parametrically;
What about calculating on a specific surface for example an triangle?
Btw, I have forgotten Green theorem, Is it time consuming to use it claculate a double integral on CP?
but if you want it parametrically;
What about calculating on a specific surface for example an triangle?
Btw, I have forgotten Green theorem, Is it time consuming to use it claculate a double integral on CP?
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