How could I draw in parametric style the folium of descartes complete?I mean after I plot the curve it only traces half of the graph..what happened to the rest for example the part that has asymptotic value near infinit?

# Hard specific question--Descartes folium...

Started by
epaloco
, Apr 04 2003 03:28 PM

3 replies to this topic

### #1

Posted 04 April 2003 - 03:28 PM

### #2

Posted 04 April 2003 - 05:54 PM

(I assume you mean the parametric graph: x = 3aT/(1+T^3), y = 3aT^2/(1+T^3) , from the cartesian: X^3 + Y^3 = 3AXY )

these points are true for the equation when x and y reaches +/- infinity, but can no be obtained through paramtric graphing, since the parametric function will leave x and y going towards 0 as T reaches infinite

the function for your asymptotes would be: y = -a -x

you would need a conics program to draw the whole graph correctly (the one on calc doesn't have this function)

these points are true for the equation when x and y reaches +/- infinity, but can no be obtained through paramtric graphing, since the parametric function will leave x and y going towards 0 as T reaches infinite

the function for your asymptotes would be: y = -a -x

you would need a conics program to draw the whole graph correctly (the one on calc doesn't have this function)

### #3

Posted 04 April 2003 - 07:07 PM

hey thanks! I understand!

Where could I find that marvellous program?

Thnaks very much...! =)

Where could I find that marvellous program?

Thnaks very much...! =)

### #4

Posted 04 April 2003 - 07:14 PM

here is exactly what i want to graph....it has a bucle lets say a loop that is not draw...

x(t)=t(1+t^3)

y(t)=t^2(1+t^3)

or for example Diocles Cisoide

a(t)=((t^2+1)/(2at^3/(1+t^2))

thanks!

x(t)=t(1+t^3)

y(t)=t^2(1+t^3)

or for example Diocles Cisoide

a(t)=((t^2+1)/(2at^3/(1+t^2))

thanks!

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