I surprised a lot qhe i put the following matrix
68.75 0 0
0 68.75 0
0 0 0
I executed the eigVc command and I obtained
1 0.707 0
0 -0707 0
0 0 1
I almost died when i saw this!!!
How can I fix this???
PS: If u dont realize...the first column is not ortogonal with 2nd column....its suppused that i should get the ijk vector system....
Miscalculated Eigen Vectors
Started by
aacs88
, Nov 26 2007 01:55 AM
7 replies to this topic
#1
aacs88
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Posted 26 November 2007 - 01:55 AM
#2
aacs88
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Posted 28 November 2007 - 02:58 AM
please answer
!!!!
!!!!
#3
Orwell
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Posted 01 December 2007 - 10:57 AM
On my classpad it gives
0 1 0
1 0 0
0 0 1
which is normal because your matrix is already diagonal.
0 1 0
1 0 0
0 0 1
which is normal because your matrix is already diagonal.
#4
aacs88
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Posted 02 December 2007 - 12:39 PM
so there is a problem with my class pad
what can i do?
what can i do?
#5
Guest_Guest_*
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Posted 01 April 2008 - 01:20 AM
Plz i still dont get any answers
#6
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Posted 01 April 2008 - 09:35 AM
Do you use OS (Operating System) ver. 2.2?
#7
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Posted 01 April 2008 - 08:26 PM
I surprised a lot qhe i put the following matrix
68.75 0 0
0 68.75 0
0 0 0
I executed the eigVc command and I obtained
1 0.707 0
0 -0707 0
0 0 1
I almost died when i saw this!!!
How can I fix this???
PS: If u dont realize...the first column is not ortogonal with 2nd column....its suppused that i should get the ijk vector system....
aacs88:
Definition: let A be a square matrix and k is the eigenvalue of A if there exist nonzero vector P such that AP=kP . every nonzero vector P is called eigenvector of A associated with the eigenvalue k. this implies that both side are parallel vectors.
According to this definition your answer is correct. Since your eigenvalue are
k1 =68.75
k2=68.75
k3=0
then
|68.75 0 0||1| |1|
|0 68.75 0||0|= k1 |0|
|0 0 0||0| |0|
also
|68.75 0 0||0.707 | |0.707 |
|0 68.75 0||-0.707 |=k2 |-0.707|
|0 0 0| | 0 | | 0 |
And
|68.75 0 0||0| |0|
|0 68.75 0||0|= k3 |0|
|0 0 0||1| |1|
Notice that these eigenvectors are not unique i.e. there are infinitely many possible solutions as long as they satisfy AP=kP.
|0 1 0|
|1 0 0| is also a possible solution
|0 0 1|
The eigenvectors are not necessarily orthogonal, for your case you have a repeated eigenvalues in the diagonal matrix.
On my classpad it gives
0 1 0
1 0 0
0 0 1
which is normal because your matrix is already diagonal.
Orwell:
I've tried to solve this problem with my CP it gave me the answer
1 0.707 0
0 -0.707 0
0 0 0
I'm running OS v3.03, what method did you use to calculate the eigenvectors ?
Inform me please.
#8
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Posted 10 April 2008 - 11:41 PM
On an AFX 2.0+ I got the EigenVectors
1 1 0
0 0 0
0 0 1
for the EigenValues
68.75 68.75 0
Just my two cents
1 1 0
0 0 0
0 0 1
for the EigenValues
68.75 68.75 0
Just my two cents
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