Hello
I want to solve a matrix with four unkown variables, i went to the variable manager and i saw that there was only one variable.
is that the problem?How can i addm more variables or solve the eqution?
thank you
Problem With A Matrix
Started by
maxxwell
, Dec 19 2007 04:59 PM
2 replies to this topic
#1
Posted 19 December 2007 - 04:59 PM
#2
Posted 21 December 2007 - 02:36 AM
Try to make only one topic. posting two topics for the same thing will not get you double the answers.
Back in topic. a matrix is a variable, when you solve a linear system usin matrix algebra, the result is still a matrix. You need to extract the solution from that matrix..
So, if you want to solve a system and see every variable, you can do it using the
{
function on your 2D keyboard. you'll need to tap it several times to make it bigger (ie, to accomodate more ecuations)
As a example:
{ 2x + 3y =0 |
5y-12x = 2 |x,y
will give you x=-3/23 and y=2/23
In matrix form you can do:
rref( 2 3 0
-12 5 2
and you'll get
1 0 -3/23
0 1 2/23
Back in topic. a matrix is a variable, when you solve a linear system usin matrix algebra, the result is still a matrix. You need to extract the solution from that matrix..
So, if you want to solve a system and see every variable, you can do it using the
{
function on your 2D keyboard. you'll need to tap it several times to make it bigger (ie, to accomodate more ecuations)
As a example:
{ 2x + 3y =0 |
5y-12x = 2 |x,y
will give you x=-3/23 and y=2/23
In matrix form you can do:
rref( 2 3 0
-12 5 2
and you'll get
1 0 -3/23
0 1 2/23
#3
Posted 21 December 2007 - 02:34 PM
Sorry i'm i am stil a rookie in managing forum and thank you for the help
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