Hello

I want to solve a matrix with four unkown variables, i went to the variable manager and i saw that there was only one variable.

is that the problem?How can i addm more variables or solve the eqution?

thank you

# Problem With A Matrix

Started by
maxxwell
, Dec 19 2007 04:59 PM

2 replies to this topic

### #1

Posted 19 December 2007 - 04:59 PM

### #2

Posted 21 December 2007 - 02:36 AM

Try to make only one topic. posting two topics for the same thing will not get you double the answers.

Back in topic. a matrix is a variable, when you solve a linear system usin matrix algebra, the result is still a matrix. You need to extract the solution from that matrix..

So, if you want to solve a system and see every variable, you can do it using the

{

function on your 2D keyboard. you'll need to tap it several times to make it bigger (ie, to accomodate more ecuations)

As a example:

{ 2x + 3y =0 |

5y-12x = 2 |x,y

will give you x=-3/23 and y=2/23

In matrix form you can do:

rref( 2 3 0

-12 5 2

and you'll get

1 0 -3/23

0 1 2/23

Back in topic. a matrix is a variable, when you solve a linear system usin matrix algebra, the result is still a matrix. You need to extract the solution from that matrix..

So, if you want to solve a system and see every variable, you can do it using the

{

function on your 2D keyboard. you'll need to tap it several times to make it bigger (ie, to accomodate more ecuations)

As a example:

{ 2x + 3y =0 |

5y-12x = 2 |x,y

will give you x=-3/23 and y=2/23

In matrix form you can do:

rref( 2 3 0

-12 5 2

and you'll get

1 0 -3/23

0 1 2/23

### #3

Posted 21 December 2007 - 02:34 PM

Sorry i'm i am stil a rookie in managing forum and thank you for the help

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