hi

see this

if I want to calculate Var.P on CP400, what should I do ??

**Edited by Ata.H.D, 08 July 2015 - 05:28 PM.**

Started by
Ata.H.D
, Jul 08 2015 10:01 AM

5 replies to this topic

Posted 08 July 2015 - 10:01 AM

hi

see this

if I want to calculate Var.P on CP400, what should I do ??

**Edited by Ata.H.D, 08 July 2015 - 05:28 PM.**

Posted 08 July 2015 - 05:27 PM

Before starting I do some math first. You can compute Var.P by using of 2 methods:

1. method

Var.P=Var.S*(n-1)/n, Var.S is computed by ClassPad (command variance)

2. method

Var.P = (sigmax)^{2 }, where sigmax means population standard deviation

similarly

Var.S = (sx)^{2} , where sx means sample standard deviation

------------------------------------------------------------------------------------------------------------

**the 1st method is suitable for list calculation,**

Var.P = variance(list1)*(dim(list1)-1)/dim(list1), the list1 is used

in your case:

Var.S = variance = 27130, n=dim(list1)=5

Var.P = 27130*(5-1)/5

Var.P = 21704

**the 2nd method is suitable for spreadsheet calculation, because the sigmax is calculated**

sigmax = 26.0546, computed value

Var.P = sigmax^{2}

Var.P =147.323^{2} = 21704

sx = 164.712, computed value

Var.S = sx^{2}

Var.S =164.712^{2} = 27130 ^{ }

- Ata.H.D likes this

Posted 08 July 2015 - 05:38 PM

Before starting I do some math first. You can compute Var.P by using of 2 methods:

1. method

Var.P=Var.S*(n-1)/n, Var.S is computed by ClassPad (command variance)

2. method

Var.P = (sigmax)

^{2 }, where sigmax means population standard deviation

similarly

Var.S = (sx)

^{2}, where sx means sample standard deviation------------------------------------------------------------------------------------------------------------

the 1st method is suitable for list calculation,

Var.P = variance(list1)*(dim(list1)-1)/dim(list1), the list1 is used

in your case:

Var.S = variance = 27130, n=dim(list1)=5

Var.P = 27130*(5-1)/5

Var.P = 21704

the 2nd method is suitable for spreadsheet calculation, because the sigmax is calculated

sigmax = 26.0546, computed value

Var.P = sigmax

^{2}Var.P =147.323

^{2}= 21704

sx = 164.712, computed value

Var.S = sx

^{2}Var.S =164.712

^{2}= 27130^{ }

TanQ

but wich 1 is true??

Eg. I got these on exam!! what should I do??

Posted 08 July 2015 - 06:35 PM

Sorry, I don't understand what you mean : "but which 1 is true??"

Both methods of computation are correct.

Differences between Population and sample standard deviations

http://libweb.surrey...ter/page_18.htm

- Ata.H.D likes this

Posted 10 July 2015 - 10:04 AM

It's interesting much cheaper Classwizz computes both values directly

http://abload.de/img...11542228qx0.jpg

- Ata.H.D likes this

Posted 10 July 2015 - 03:03 PM

It's interesting much cheaper Classwizz computes both values directly

OMG !!!!

hi

after e-mail , I got this

**Edited by Ata.H.D, 13 July 2015 - 01:23 PM.**

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