Math's doubts
#1
Posted 03 November 2003 - 01:36 AM
Today i had this one, hope that someone can understand & help me:
I have this math expression:
1 + a + a^2 + a^3 + .... (it spreads to infinite, n)
I want to re-write this via classpad (i want to apply this for exams), my teacher give us this result:
1 - a^(n+1)
1 - a
Does some classpad command do that?
#2
Posted 03 November 2003 - 02:10 PM
Procedure:
Press KeyBoard, 2D, then find the symbol for sum (upcase sigma)
In the lower box, tap x. Next, tap 1 to the right box.
Next, In the top box, input n.
In the last box, input a^x
After that, tap everywhere out of Sigma symbol and tap + 1.
Press EXE.
To get the same result with your teacher, select Action, Transformation, Combine, and tap ans, EXE. You will get the same result.
GoodLuck
Oh, what grade are you in?
#3
Posted 03 November 2003 - 10:16 PM
Right now I'm studing the 7th of 8 semester of electronic engineer.
#4
Posted 04 November 2003 - 02:01 AM
As I say above, In the lower box of Sigma symbol, you change x=1 to x=0.
Then, you dont need to +1 because a^0=1 with all a<>0. Then press EXE and you will go directly to the result.
If you have other problems, put it here so we can learn more about the ClassPad.
#5
Posted 04 November 2003 - 06:45 AM
#6
Posted 26 November 2003 - 04:48 AM
"The ModBox for represent statics variables (one dimension) dont work; its a method for determinate "outliers", but it really do the same graphic that the "box and whiskers" option."
I hope somebody can help him (i dont know and i dont like anything about statics ).
#7
Posted 30 November 2003 - 05:14 PM
y=sin(x)|x=int(x)
This work well in the classpad manager, but in the classpad no
Try this and let me know what happend...
#8
Posted 01 December 2003 - 01:42 AM
I tried the code you write, both ClassPad and the manager produced the same result: the graph window appear some dot. What did the graph window appear on your ClassPad?
Oh, could someone help me to solve: (sin(3x/2))^2=sin(x)sin(3x).
#9
Posted 01 December 2003 - 05:20 AM
Strange, other guy had the same error that me.
#10
Posted 01 December 2003 - 09:02 AM
Well,Oh, could someone help me to solve: (sin(3x/2))^2=sin(x)sin(3x).
'x=0+2k*pi' is one obvious solution
-- EDIT --
Solutions:
x = 2k*pi
x = 2/3 * pi + 2k*pi
x = pi/6 - 4/3 * pi + 2k*pi
x = -pi/6 + 4/3 * pi + 2k*pi
#11
Posted 02 December 2003 - 02:35 AM
0 user(s) are reading this topic
0 members, 0 guests, 0 anonymous users